Salt Hydrolysis Definition

Salt Hydrolysis is the interaction of salt ions with water to produce either acidic or basic solutions. It is effectively the chemical opposite of a neutralization reaction.

The extent of this reaction is called the Degree of Hydrolysis ($h$), and the equilibrium constant is the Hydrolysis Constant ($K_h$).

Mathematical Foundations

Weak Acid & Strong Base Salt:

$$\text{pH} = 7 + \frac{1}{2}(pK_a + \log C)$$

Strong Acid & Weak Base Salt:

$$\text{pH} = 7 - \frac{1}{2}(pK_b + \log C)$$

Salt Hydrolysis Solver

Example: NaCl, KNO₃, Na₂SO₄

Neutral

Guide: Entering Values

Our calculators use a smartParser to handle scientific notation.

^
Exponent: 10^5 means 105
*
Multiply: 10*1 means 10 multiplied by 1.
e
Scientific: 1.8e-5 means 1.8 × 10-5

Practical Examples:

  • Positive: Enter 10^2 for 100.
  • Negative: Enter -5 for acidic values.
  • Complex: Enter 10^-7 for neutral pH.

Salt Hydrolysis: Theory & Salt Types

What is Salt Hydrolysis?

Salt hydrolysis is a process in which the constituent ions of a salt react with water to produce either acidity or alkalinity. It is essentially the reverse of a neutralization reaction.

The Four Salt Categories
  • SA/SB (e.g., NaCl): No hydrolysis occurs. Solution remains neutral (pH ≈ 7).
  • WA/SB (e.g., CH₃COONa): Anionic hydrolysis occurs. Solution becomes Basic (pH > 7).
  • SA/WB (e.g., NH₄Cl): Cationic hydrolysis occurs. Solution becomes Acidic (pH < 7).
  • WA/WB (e.g., NH₄CH₃COO): Both ions hydrolyze. pH depends on relative $K_a$ and $K_b$ values.

Calculation Example (WA/SB Salt)

Problem: Calculate the pH of a $0.1\text{ M}$ Sodium Acetate solution ($K_a \text{ of acetic acid} = 1.8 \times 10^{-5}$).

Formula: $pH = 7 + \frac{1}{2}[pK_a + \log C]$

Steps:
  • $pK_a = -\log(1.8 \times 10^{-5}) = 4.74$
  • $pH = 7 + \frac{1}{2}[4.74 + \log(0.1)]$
  • $pH = 7 + \frac{1}{2}[4.74 - 1] = 7 + 1.87$
  • Result: $\mathbf{pH = 8.87}$

Research & Analytical Techniques

Degree of Hydrolysis ($h$)

In research labs, the degree of hydrolysis is often determined via Conductometric Titration. As hydrolysis progresses, the change in ion mobility alters the solution's conductivity.

UV-Vis Spectroscopy

For salts of organic acids/bases, the change in absorption spectra due to hydrolysis allows scientists to calculate the hydrolysis constant ($K_h$) with extreme precision.

Unique Hydrolysis Facts

Antacid Effect: Baking soda ($NaHCO_3$) works as an antacid because the bicarbonate ion undergoes hydrolysis to produce $OH^-$ ions, neutralizing stomach acid.

Soil pH: Many fertilizers are salts (like Ammonium Sulfate). Their hydrolysis in soil moisture can significantly lower soil pH, affecting crop yield.

Amphiprotic Ions: Salts like $NaH_2PO_4$ can either donate or accept protons depending on the environment, making their hydrolysis calculations uniquely complex.

Expert FAQ: Salt Equilibrium

Why doesn't $NaCl$ hydrolyze?

$Na^+$ and $Cl^-$ are conjugate partners of strong bases/acids. They have negligible affinity for $H^+$ or $OH^-$ ions in water.

What is the Hydrolysis Constant ($K_h$)?

It is the equilibrium constant for the hydrolysis reaction. For a WA/SB salt, $K_h = K_w / K_a$.

How does concentration affect hydrolysis?

As concentration ($C$) decreases, the degree of hydrolysis ($h$) increases, though the total shift in pH might become less extreme.

Can a salt of WA/WB be neutral?

Yes. If $K_a$ of the weak acid exactly equals $K_b$ of the weak base (e.g., Ammonium Acetate), the pH remains 7.0.

What is Cationic Hydrolysis?

When the cation (usually from a weak base) reacts with water to release $H_3O^+$ ions, making the solution acidic.

Is hydrolysis endothermic?

Generally, yes. Increasing the temperature usually increases the degree of hydrolysis.

How does $h$ relate to $K_h$?

For dilute solutions where $h < 0.1$, the relation is $h = \sqrt{K_h / C}$.

What is the pH of $AlCl_3$?

Very acidic (pH ≈ 2-3). The $Al^{3+}$ ion has a high charge density, polarizing water molecules to release $H^+$ ions.

Does $K_w$ change the result?

Yes. Since $K_h$ depends on $K_w$, any temperature change that shifts $K_w$ will shift the hydrolysis equilibrium.