Advanced Chemistry Calculators

Electromotive Force (EMF)

The **Electromotive Force (EMF)** of a cell is the maximum potential difference between two electrodes when no current is flowing through the circuit. It represents the energy provided by a source per unit charge.

Standard Cell Potential: $E^0_{cell} = E^0_{cathode} - E^0_{anode}$
Nernst Equation: $E_{cell} = E^0_{cell} - \frac{RT}{nF} \ln Q$
Standard Cell Potential
Non-Standard EMF (Nernst)
EMF to Free Energy
Molar Conductivity ($\Lambda_m$)
$\Lambda_m = \frac{\kappa \times 1000}{C}$
Kohlrausch's Law Calculator
Standard Reduction Potentials ($E^0$ at 25°C)
Half-Reaction$E^0$ (Volts)
$F_2(g) + 2e^- \rightarrow 2F^-(aq)$+2.87
$Au^{3+}(aq) + 3e^- \rightarrow Au(s)$+1.50
$Cl_2(g) + 2e^- \rightarrow 2Cl^-(aq)$+1.36
$Ag^+(aq) + e^- \rightarrow Ag(s)$+0.80
$Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)$+0.34
$2H^+(aq) + 2e^- \rightarrow H_2(g)$0.00
$Ni^{2+}(aq) + 2e^- \rightarrow Ni(s)$-0.25
$Fe^{2+}(aq) + 2e^- \rightarrow Fe(s)$-0.44
$Zn^{2+}(aq) + 2e^- \rightarrow Zn(s)$-0.76
$Al^{3+}(aq) + 3e^- \rightarrow Al(s)$-1.66
$Li^+(aq) + e^- \rightarrow Li(s)$-3.05

Guide: Entering Values

Our calculators use a smartParser to handle scientific notation.

^
Exponent: 10^5 means 105
*
Multiply: 10*1 means 10 multiplied by 1.
e
Scientific: 1.8e-5 means 1.8 × 10-5

Practical Examples:

  • Positive: Enter 10^2 for 100.
  • Negative: Enter -5 for acidic values.
  • Complex: Enter 10^-7 for neutral pH.
EMF of Cell vs. Battery

While often used interchangeably, a **Cell** is a single unit of an electrochemical device, whereas a **Battery** consists of multiple cells connected in series or parallel to increase voltage or capacity.

How it Works

EMF is generated by the chemical potential difference between two materials. When a redox reaction occurs, electrons are pushed from the anode (oxidation) through an external circuit to the cathode (reduction). The "force" driving this flow is the EMF.

Applications
Solved Examples
Example 1: Calculate the standard EMF of a Zn-Cu cell.
$E^0_{Cu^{2+}/Cu} = +0.34V$, $E^0_{Zn^{2+}/Zn} = -0.76V$.
$E^0_{cell} = 0.34 - (-0.76) = 1.10V$.

Example 2: Find $\Delta G$ for a cell with $E_{cell} = 1.10V$ and $n=2$.
$\Delta G = -nFE_{cell} = -(2)(96500)(1.10) = -212.3$ kJ/mol.
Scientific Research & Future Tech

In modern electrochemistry, EMF measurements are pivotal for:

Frequently Asked Questions