Cell Potential Calculator
Calculate standard, non-standard, and Nernst cell potentials instantly. Powered by reduction potential tables, the Nernst equation, and Gibbs free energy relationships.
What is Cell Potential?
Cell Potential (Ecell), also called electromotive force (EMF), is the driving force that pushes electrons through an external circuit in an electrochemical cell. It is measured in Volts (V) and determines whether a redox reaction occurs spontaneously or non-spontaneously.
It represents the difference in reduction potential between the cathode (reduction) and the anode (oxidation). A positive Ecell indicates a spontaneous reaction (ΔG < 0), while a negative value indicates non-spontaneity.
Core Formulas
Symbol Reference
Cell Potential Calculator
Enter the standard reduction potentials for cathode and anode to calculate E°cell. You can use preset half-reactions or enter custom values.
Calculate the actual cell potential at non-standard conditions using the Nernst equation.
Calculate Gibbs free energy (ΔG°) and equilibrium constant (K) from standard cell potential.
How to Use This Calculator
Follow these steps to get accurate results. Each mode uses different inputs — here's a complete guide with real examples.
Detailed Worked Example — Nernst Mode
Given: Cu²⁺/Cu cathode (+0.34 V), Zn²⁺/Zn anode (−0.76 V). [Cu²⁺] = 0.5 M, [Zn²⁺] = 0.1 M, T = 298 K, n = 2
Interpretation: The non-standard potential (+1.121 V) is slightly higher than E°cell because reactant concentration (Cu²⁺) is lower than standard, favouring the forward reaction.
Key Aspects of Cell Potential
Understanding these aspects enables deeper analysis of electrochemical systems across all scales.
Applications & Uses of Cell Potential
Cell Potential Calculation — Step-by-Step
Follow this systematic approach to solve any cell potential problem confidently.
Example: Cu²⁺ + 2e⁻ → Cu (reduction) | Zn → Zn²⁺ + 2e⁻ (oxidation)
E°(Cu²⁺/Cu) = +0.34 V | E°(Zn²⁺/Zn) = −0.76 V
Cathode: Cu²⁺/Cu (+0.34 V) — higher | Anode: Zn/Zn²⁺ (−0.76 V) — lower
E°cell = (+0.34) − (−0.76) = +1.10 V
If [Cu²⁺] = 0.5 M and [Zn²⁺] = 0.1 M: Q = 0.1/0.5 = 0.2
ΔG° = −2 × 96485 × 1.10 = −212,267 J = −212.3 kJ/mol
Solved Examples
Cell: Zn | Zn²⁺(1M) || Cu²⁺(1M) | Cu
Given: E°(Cu²⁺/Cu) = +0.34 V, E°(Zn²⁺/Zn) = −0.76 V, n = 2
Conclusion: This galvanic cell spontaneously converts chemical energy to electrical energy.
Given: E°(Ag⁺/Ag) = +0.80 V, E°(Zn²⁺/Zn) = −0.76 V, n = 2
Conclusion: Extremely large K confirms this reaction goes essentially to completion.
Given: Electrolysis of NaCl(aq). E°(Cl₂/Cl⁻) = +1.36 V (cathode?), E°(O₂/H₂O) = +1.23 V
For the desired reaction (Cl₂ at anode, H₂ at cathode): E°cell = 0.00 − 1.36 = −1.36 V
Conclusion: Minimum 1.36 V external voltage required. In practice, overpotential makes it ~2 V in industrial chlor-alkali plants.
Given: Glass electrode, E°cell = 0.40 V, n = 1, T = 298 K, Q = [H⁺] = 10⁻³ M (pH 3)
Conclusion: Each pH unit change alters E by 59.2 mV at 25°C — the basis of all pH meters.
Rules & Principles
Standard Reduction Potentials — Reference Table
Selected values at 25°C, 1 M concentration, 1 atm for gases. Ordered from most oxidizing (top) to most reducing (bottom).
| Half-Reaction | E° (V) | Category | Common Use |
|---|---|---|---|
| F₂ + 2e⁻ → 2F⁻ | +2.87 | Strong Oxidizer | Fluorine chemistry |
| MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O | +1.51 | Oxidizer | Titrations |
| Cl₂ + 2e⁻ → 2Cl⁻ | +1.36 | Oxidizer | Chlor-alkali industry |
| O₂ + 4H⁺ + 4e⁻ → 2H₂O | +1.23 | Oxidizer | Fuel cells, corrosion |
| Ag⁺ + e⁻ → Ag | +0.80 | Metal | Silver plating |
| Fe³⁺ + e⁻ → Fe²⁺ | +0.77 | Redox | Iron chemistry |
| Cu²⁺ + 2e⁻ → Cu | +0.34 | Metal | Copper plating, Daniell cell |
| 2H⁺ + 2e⁻ → H₂ | 0.00 | SHE Reference | Universal reference |
| Pb²⁺ + 2e⁻ → Pb | −0.13 | Metal | Lead-acid batteries |
| Ni²⁺ + 2e⁻ → Ni | −0.25 | Metal | Nickel cells |
| Fe²⁺ + 2e⁻ → Fe | −0.44 | Metal | Iron redox |
| Zn²⁺ + 2e⁻ → Zn | −0.76 | Reducer | Daniell cell, galvanizing |
| Al³⁺ + 3e⁻ → Al | −1.66 | Strong Reducer | Aluminum smelting |
| Mg²⁺ + 2e⁻ → Mg | −2.37 | Strong Reducer | Sacrificial anodes |
| Na⁺ + e⁻ → Na | −2.71 | Strong Reducer | Sodium batteries |
| Li⁺ + e⁻ → Li | −3.04 | Strongest Reducer | Li-ion batteries |
How Cell Potential Works — Mechanism
At the atomic level, cell potential arises from the difference in electron affinity between two metals. Here's the complete mechanism with a concrete Daniell cell example:
Zinc atoms lose electrons (oxidation) and dissolve into solution as Zn²⁺ ions. The electrode becomes negatively charged as electrons accumulate.
Cu²⁺ ions from solution gain electrons (reduction) and deposit as solid copper. This electrode becomes positive.
Ions migrate through the salt bridge to maintain electrical neutrality: anions flow to the anode, cations flow to the cathode compartment.
Electrons flow through the external circuit from anode (−) to cathode (+), driven by the potential difference E°cell = 1.10 V.
Energy Conversion Chain
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Cell Potential in Scientific Research
Researchers across disciplines rely on electrochemical potential measurements for cutting-edge applications.
Frequently Asked Questions
Comprehensive answers to the most common questions about cell potential and electrochemistry.